If F(z)= log z, show that F(xy) = F(x) +F(y).
F(xy)=log(xy)=log(x)+log(y)=F(x)+F(y)F(xy) = \log (xy) = \log (x) + \log (y) = F(x) + F(y)F(xy)=log(xy)=log(x)+log(y)=F(x)+F(y)
Q.E.D.
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