Answer to Question #346823 in Calculus for andrew

Question

dy/dx + 4y= 8

Answer 1

$$dy/dx=-4y+8$$

$$\dfrac{dy}{y-2}=-4dx$$

Integrate

$$\int\dfrac{dy}{y-2}=-\int4dx$$

$$\ln|y-2|=-4x+\ln C$$

$$|y-2|=Ce^{-4x}$$