Question #346823

dy/dx + 4y= 8



1
Expert's answer
2022-06-03T02:52:20-0400
dy/dx=4y+8dy/dx=-4y+8

dyy2=4dx\dfrac{dy}{y-2}=-4dx

Integrate


dyy2=4dx\int\dfrac{dy}{y-2}=-\int4dx

lny2=4x+lnC\ln|y-2|=-4x+\ln C

y2=Ce4x|y-2|=Ce^{-4x}


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