Answer to Question #346638 in Calculus for Main

Question

∫ (𝑥2²+ 5)³2𝑥𝑑𝑥

Answer 1

$$\int(x^2+5)^32xdx$$

$u=x^2+5, du=2xdx$

$$\int(x^2+5)^32xdx=\int u^3du=\dfrac{u^4}{4}+C$$ $$=\dfrac{(x^2+5)^4}{4}+C$$