Question #346438

Differentiate with respect to 𝑥

a. (7𝑥 – 4 )3

b. √(6𝑥+4)


1
Expert's answer
2022-06-02T06:24:21-0400

a. ((7x4)3)=3(7x4)27=21(7x4)2\big((7x-4)^3\big)^\prime =3(7x-4)^2\cdot 7=21(7x-4)^2

b. (6x+4)=((6x+4)1/2)=12(6x+4)1/26=36x+4\big(\sqrt{6x+4}\big)^\prime =\big((6x+4)^{1/2}\big)^\prime=\tfrac{1}{2}(6x+4)^{-1/2}\cdot 6=\frac{3}{\sqrt{6x+4}}


Answers: a. 21(7x4)2;21(7x-4)^2; b. 36x+4.\frac{3}{\sqrt{6x+4}}.


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