Answer to Question #346048 in Calculus for Lenard

Question

f(×)=6/ײ3×-10

a. X=-2

b. x= 0

c. x=5

Answer 1

$$f(x)=\dfrac{6}{x^2-3x-10}$$

$$x^2-3x-10\not=0$$

$$(x+2)(x-5)\not=0$$

$$x\not=-2, x\not=5$$

Domain: $(-\infin, -2)\cap (-2, 5)\cap(5, \infin)$

a.

$$f(-2)=\dfrac{6}{(-2)^2-3(-2)-10} , undefined$$

$f(-2)$ is undefined.

b.

$$f(0)=\dfrac{6}{(0)^2-3(0)-10}=-\dfrac{3}{5}$$

$f(0)=-\dfrac{3}{5}$ .

c.

$$f(5)=\dfrac{6}{(5)^2-3(5)-10} , undefined$$

$f(5)$ is undefined.