Question #344649

Calculate the definite integral y = 𝑡 ^3 + 2𝑒 ^ 4𝑡 + 1/ 𝑡 + 3 sin 2𝑡)


1
Expert's answer
2022-05-25T15:57:23-0400
y=(𝑡3+2𝑒4t+1t+3sin(2𝑡))dty=\int (𝑡 ^3 + 2𝑒 ^ {4t} + \dfrac{1}{t} + 3 \sin (2𝑡))dt

=t44+12e4t+lnt32cos(2t)+C=\dfrac{t^4}{4}+\dfrac{1}{2}e^{4t}+\ln|t|-\dfrac{3}{2}\cos(2t)+C


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