Answer to Question #344332 in Calculus for Jane

Question #344332

6. A force of 20 lb stretches a spring from a natural length of 7 inches to a length of 12 inches. How much work was performed in stretching the spring to this length?

1
Expert's answer
2022-05-30T16:56:35-0400
"F=k\\Delta x"

"k=\\dfrac{F}{x_2-x_1}"

"=\\dfrac{20\\ lb}{12\\ in-7\\ in}=4\\ lb\/in"

"W=\\dfrac{k(\\Delta x)^2}{2}"

"=\\dfrac{4\\ lb\/in(12\\ in-7\\ in)^2}{2}=50\\ lb\\cdot in"


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