Question #344327

3. A force of F(x)=x²-cos(3x) +2, x is in meters, acts on an object. What is the work required to move the object from x=3 to x=7?

1
Expert's answer
2022-05-26T17:05:17-0400
W=37(x2cos(3x)+2)dxW=\displaystyle\int_{3}^{7}(x^2-\cos(3x) +2)dx

=[x3313sin(3x)+2x]73=[\dfrac{x^3}{3}-\dfrac{1}{3}\sin (3x)+2x]\begin{matrix} 7 \\ 3 \end{matrix}

=343313sin(21)+14=\dfrac{343}{3}-\dfrac{1}{3}\sin (21)+14

(27313sin(9)+6)-(\dfrac{27}{3}-\dfrac{1}{3}\sin (9)+6)

=340313sin(21)+13sin(9)=\dfrac{340}{3}-\dfrac{1}{3}\sin (21)+\dfrac{1}{3}\sin (9)


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