Determine the area of the given curves
1 . 𝑦2 = 2 𝑥 ; 𝑦 = 𝑥 − 4
2. 𝑦 = 𝑥 − 𝑥2 ; 𝑦 = − 𝑥
1) 𝑦2 = 2 𝑥 ; 𝑦 = 𝑥 − 4
S=∫\int∫-24(y+4-y2/2)dy=(y2/2+4y-y3/6)∣\mid∣-24=8+16-64/6-2+8-8/6=30-32/3-4/3=30-36/3=30-12=18
2) 𝑦 = 𝑥 − 𝑥2 ; 𝑦 = − 𝑥
S=∫\int∫02(x-x2+x)dx=∫\int∫02(2x-x2) dx=(x2-x3/3)∣\mid∣02=4-8/3=4/3
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