Question #340773

Solve using basic differentiation rule


𝑠 = (𝑡^2 − 3)^4

1
Expert's answer
2022-05-16T10:33:07-0400

𝑠(x)=4(t23)3(t2)=8t(t23)3𝑠’(x)=4(t^2-3)^3(t^2)’=8t(t^2-3)^3


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