Solve using basic differentiation rule
š = (š”^2 ā 3)^4
š ā(x)=4(t2ā3)3(t2)ā=8t(t2ā3)3š ā(x)=4(t^2-3)^3(t^2)ā=8t(t^2-3)^3sā(x)=4(t2ā3)3(t2)ā=8t(t2ā3)3
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