Question #340773

Solve using basic differentiation rule


š‘  = (š‘”^2 āˆ’ 3)^4

Expert's answer

š‘ ā€™(x)=4(t2āˆ’3)3(t2)’=8t(t2āˆ’3)3š‘ ā€™(x)=4(t^2-3)^3(t^2)’=8t(t^2-3)^3


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