Solve using basic differentiation rule
𝑠 = (𝑡^2 − 3)^4
𝑠’(x)=4(t2−3)3(t2)’=8t(t2−3)3𝑠’(x)=4(t^2-3)^3(t^2)’=8t(t^2-3)^3s’(x)=4(t2−3)3(t2)’=8t(t2−3)3
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