Answer to Question #340770 in Calculus for Jayson

Question

Solve using basic differentiation rule

𝑔(𝑥) =3−2𝑥/3+2𝑥

Answer 1

$\frac{d}{dx}(3-\frac{2x}{3}+2x)=g’(x)$

$g’(x)=-\frac{2}{3}+2=\frac{4}{3}$