Answer to Question #340770 in Calculus for Jayson

Question #340770

Solve using basic differentiation rule

𝑔(𝑥) =3−2𝑥/3+2𝑥

Expert's answer

"\\frac{d}{dx}(3-\\frac{2x}{3}+2x)=g\u2019(x)"

"g\u2019(x)=-\\frac{2}{3}+2=\\frac{4}{3}"

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