Question #340770

Solve using basic differentiation rule


š‘”(š‘„) =3āˆ’2š‘„/3+2š‘„

Expert's answer

ddx(3āˆ’2x3+2x)=g’(x)\frac{d}{dx}(3-\frac{2x}{3}+2x)=g’(x)

g’(x)=āˆ’23+2=43g’(x)=-\frac{2}{3}+2=\frac{4}{3}


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