Question #339325

Use the Lagrange multipliers to solve the following:

Maximize f(x,y,z) = 4x + 2y + z

subject to x2 + y + z2 = 1


1
Expert's answer
2022-05-10T23:39:18-0400

Let’s define g(x,y,z)=x2+y+z2,g(x, y, z) = x^ 2 +y +z^ 2 , so the problem is to find the maximum of f(x,y,z)f(x, y, z) subject to the constraint g(x,y,z)=1.g(x, y, z) = 1. We have 


f=λg\nabla f=\lambda \nabla g

4,2,1=λ2x,1,2z\langle4,2,1\rangle=\lambda\langle2x,1,2z\rangle

Reading this component by component and including the restriction we get the system of equations 


4=2λx4=2\lambda x

2=λ2=\lambda

1=2λz1=2\lambda z

x2+y+z2=1x^ 2 +y+z^ 2=1

Then x=1,z=14,λ=2.x=1, z=\dfrac{1}{4}, \lambda=2.


1+y+116=11+y+\dfrac{1}{16}=1


y=116y=-\dfrac{1}{16}

The maximum of ff occurs when x=1,y=116,z=14.x=1, y=-\dfrac{1}{16}, z=\dfrac{1}{4}.

f(1,116,14)=4(1)+2(116)+14=338f(1,-\dfrac{1}{16},\dfrac{1}{4}) = 4(1) + 2(-\dfrac{1}{16}) + \dfrac{1}{4}=\dfrac{33}{8}


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