If I=V/R and V=250 volts and R=50ohms,find the change in I resulting from an increase of 2 volts in v and an increase of 0.5ohm in R. Using total differential method.
The total differential for I is
"dI=\\frac{1}{R}dV-\\frac{V}{R^2}dR"
Approximations: given small values for "\\Delta V" and "\\Delta R" :
"\\Delta I=\\frac{1}{R}\\Delta V-\\frac{V}{R^2}\\Delta R=\\frac{2}{50}-\\frac{250\\cdot 0.5}{50^2}=-0.01"
Answer: "\\Delta I=-0.01" A.
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