Assume that 10 ft-lb of work is required to stretch a spring 1 ft beyond its natural length. What is the spring constant?
W=∫abkxdx=k∫abxdx=k(x2/2)∣ab=k(b2/2−a2/2)W=\int^b_a kxdx=k\int^b_axdx=k(x^2/2)|^b_a =k(b^2/2-a^2/2)W=∫abkxdx=k∫abxdx=k(x2/2)∣ab=k(b2/2−a2/2)
W=10
a=0
b=1
10=k(1/2−0)=k/210=k(1/2-0)=k/210=k(1/2−0)=k/2
k=20
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