Question #335937

Assume that 10 ft-lb of work is required to stretch a spring 1 ft beyond its natural length. What is the spring constant?


1
Expert's answer
2022-05-03T13:58:04-0400

W=abkxdx=kabxdx=k(x2/2)ab=k(b2/2a2/2)W=\int^b_a kxdx=k\int^b_axdx=k(x^2/2)|^b_a =k(b^2/2-a^2/2)

W=10

a=0

b=1

10=k(1/20)=k/210=k(1/2-0)=k/2

k=20


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