Question #335265

Assume that 10 ft-lb of work is required to stretch a spring 1 ft beyond its natural length. What is the spring constant?

Expert's answer

W=∫abkxdx=k∫abxdx=k(x2/2)∣ab=k(b2/2−a2/2)W=\int^b_a kxdx=k\int^b_axdx=k(x^2/2)|^b_a =k(b^2/2-a^2/2)

W=10

a=0

b=1

10=k(1/2−0)=k/210=k(1/2-0)=k/2

k=20




LATEST TUTORIALS
APPROVED BY CLIENTS