Find the volume of the solid obtained by rotating the region enclosed by 𝑥=√6sin(𝑦)
and 𝑥=0
about the 𝑦-
axis over the interval 0≤𝑦≤𝜋.
Volume can be calculated by the formula:
V=π∫0π(6siny)2dy=π∫0π6sinydy=V=\pi\int_0^\pi(\sqrt{6\sin{y}})^2dy=\pi\int_0^\pi6\sin{y}dy=V=π∫0π(6siny)2dy=π∫0π6sinydy=−6πcosy∣0π=−6π(−1−1)=12π-6\pi\cos{y}|_0^\pi=-6\pi(-1-1)=12\pi−6πcosy∣0π=−6π(−1−1)=12π
Answer: V=12πV=12\piV=12π .
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