Question #334711

Provide all detailed steps to find the limit of the following functions.

Lim x→∞ (e4x - e-2x) ÷ (ln(x+1)


Expert's answer

lim⁡x→∞e4x−e−2xln⁡(x+1)\lim\limits_{x\to \infin}\dfrac{e^{4x}-e^{-2x}}{\ln(x+1)}

Use L'Hôpital's rule


lim⁡x→∞e4x−e−2xln⁡(x+1)=lim⁡x→∞(e4x−e−2x)′(ln⁡(x+1))′\lim\limits_{x\to \infin}\dfrac{e^{4x}-e^{-2x}}{\ln(x+1)}=\lim\limits_{x\to \infin}\dfrac{(e^{4x}-e^{-2x})'}{(\ln(x+1))'}

=lim⁡x→∞4e4x+2e−2x1/(x+1)=lim⁡x→∞(4e4x+2e−2x)(x+1)=\lim\limits_{x\to \infin}\dfrac{4e^{4x}+2e^{-2x}}{1/(x+1)}=\lim\limits_{x\to \infin}(4e^{4x}+2e^{-2x})(x+1)

=∞=\infin


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