Question #332669

Evaluate the following integral:

∫ √9x−5dx.

 


a.    1 / 6 √(9x−5) + c


b.   1 / 6 √(9x−5)^3 + c


c.    2 / 27 √ (9x−5) + c


d.   2 / 27 √ (9x - 5) ^3 + c



Expert's answer

F(x)=9x−5F(x)=\sqrt{9x-5}

∫9x−5dx=2/27((9x−5)3+C\int\sqrt{9x-5} dx=2/27(\sqrt{(9x-5)^3}+C

u=9x-5

dx=1/9 u

1/9∫udu=2/27u3=2/27(9x−5)3+C1/9\smallint \sqrt{u}du=2/27 \sqrt{u^3}=2/27 \sqrt{(9x-5)^3} +C


Answer: d




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