Evaluate the following integral:
∫ √9x−5dx.
a. 1 / 6 √(9x−5) + c
b. 1 / 6 √(9x−5)^3 + c
c. 2 / 27 √ (9x−5) + c
d. 2 / 27 √ (9x - 5) ^3 + c
F(x)=9x−5F(x)=\sqrt{9x-5}F(x)=9x−5
∫9x−5dx=2/27((9x−5)3+C\int\sqrt{9x-5} dx=2/27(\sqrt{(9x-5)^3}+C∫9x−5dx=2/27((9x−5)3+C
u=9x-5
dx=1/9 u
1/9∫udu=2/27u3=2/27(9x−5)3+C1/9\smallint \sqrt{u}du=2/27 \sqrt{u^3}=2/27 \sqrt{(9x-5)^3} +C1/9∫udu=2/27u3=2/27(9x−5)3+C
Answer: d
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