Question #324748

𝑓(𝑥) = 2𝑥^3 + 𝑐𝑥^2 + 2𝑥



Suppose 𝑓 is differentiable on ℝ and has two roots. Show that 𝑓′ has at least one root.

1
Expert's answer
2022-04-07T09:43:22-0400

Rewrite the function in the form: f(x)=x(2x2+cx+2)f(x)=x(2x^2+cx+2). One root of equation f=0f=0 is x=0x=0. Thus, equation 2x2+cx+2=02x^2+cx+2=0 has only one root. It means that c=4c=4 and 2(x+1)2=02(x+1)^2=0. The root of the latter is x=1.x=-1. Otherwise, we receive two roots or no roots. The derivative of the function ff is: f=6x2+8x+2f'=6x^2+8x+2. Roots of equation f=0f'=0 are: x=8±412=1,13x=\frac{-8\pm4}{12}=-1,-\frac{1}{3}. Thus, there are two roots of equation f=0.f'=0.


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