Find the limit f(x),if it exists.sketch the graph of f(x).
Limit x approaching zero f(x),where f(x)=2-x,x less than or equal zero,. x+2, x>0
Since limx→0−f(x)=2=limx→0+f(x),\lim\limits_{x\to0^-}f(x)=2=\lim\limits_{x\to0^+}f(x),x→0−limf(x)=2=x→0+limf(x), then limx→0f(x)\lim\limits_{x\to0}f(x)x→0limf(x) exists, and
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