Answer to Question #321583 in Calculus for Kenny

Question #321583

Find the limit f(x),if it exists.sketch the graph of f(x).

Limit x approaching zero f(x),where f(x)=2-x,x less than or equal zero,. x+2, x>0


1
Expert's answer
2022-06-27T06:31:58-0400
limx0f(x)=limx0(2x)=20=2\lim\limits_{x\to0^-}f(x)=\lim\limits_{x\to0^-}(2-x)=2-0=2

limx0+f(x)=limx0+(x+2)=0+2=2\lim\limits_{x\to0^+}f(x)=\lim\limits_{x\to0^+}(x+2)=0+2=2

Since limx0f(x)=2=limx0+f(x),\lim\limits_{x\to0^-}f(x)=2=\lim\limits_{x\to0^+}f(x), then limx0f(x)\lim\limits_{x\to0}f(x) exists, and


limx0f(x)=2\lim\limits_{x\to0}f(x)=2

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