Find the area of the region between the x-axis and the graph of f(x) from a=-1, to b=2, if f (x)=e^2x+3
"S=\\int_{-1}^2 (e^{2x}+3)dx=(\\frac12e^{2x}+3x)|_{-1}^2=\\frac12e^{4}+6-""(\\frac12e^{-2}-3)=\\frac12(e^4-e^{-2})+9\\approx 36.231"
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