1)x=y4−2y31=4y3⋅y′−6y2⋅y′1=y′(4y3−6y2)2)y=21t4−5t−3y′=21⋅4t3−5=2t3−53)y=(x2−2)2y′=2(x2−2)⋅2x=4x(x2−2)4)y=x+71=(x+7)−1y′=−(x+7)−2=(x+7)2−15)y=x21=x−2,(12,41)y′=k=tanα=f′(x0)y′=−2x−3,y′(12)=−2(12)−3=−8641tanα=−8641y′(41)=−2(41)−3=−321tanα=−3216)y2=4x,(1,2)y=4xy′=24x1⋅4=x1y′(1)=11=1tanα=1α=4507)y=x+11,(−2,1)y′=−(x+1)21y′(−2)=−(−2+1)21=−1tanα=−1α=1350
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