Find the volume generated if the region enclosed by y = x² and the line y = 2x is revolve about the x-axis. Answer in 2 decimal places.
"y=x^2, y=2x.\\\\"
"x^2-2x=0, x(x-2)=0,\\\\\nx_1=0, x_2=2.\\\\\nV=\\pi \\int^2_0 (4x^2-x^4)dx=\\\\\n=\\pi(\\frac{4}{3}x^3-\\frac{1}{5}x^5)|^2_0=\\\\\n=\\pi(\\frac{4}{3}2^3-\\frac{1}{5}2^5)=\\\\\n=\\pi(\\frac{32}{3}-\\frac{32}{5})=\\\\\n=32\\pi(\\frac{1}{3}-\\frac{1}{5})=\\\\\n=\\frac{64\\pi}{15}=13.40"
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