Determine whether the functions ƒ(𝑥) = √4−𝑥2 is continuous on the interval
[−4,4]. Show your complete solution.
f(x)=4−x2f\left( x \right) =\sqrt{4-x^2}f(x)=4−x2 is not defined on [-4,4], since 4−42<04-4^2<04−42<0 . Hence it is not continuous on the interval.
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