1. Ć(x)=5x+3
Consider the difference
f(x+Îx)âf(x)=5(x+Îx)+3â(5x+3)=5Îxâ0 as Îxâ0, for any xâR. Therefore, this function is continuous for any xâR.
2. Ć(x)=â4x+2
Consider the difference
f(x+Îx)âf(x)=â4(x+Îx)+2â(â4x+2)=â4Îxâ0 as Îxâ0, for any xâR. Therefore, this function is continuous for any xâR.
3. Ć(x)=2x2+xâ3
Consider the difference
f(x+Îx)âf(x)=2(x+Îx)2+(x+Îx)â3â(2x2+xâ3)
=4xÎx+2(Îx)2â0 as Îxâ0, for any xâR.
Therefore, this function is continuous for any xâR.
4. Ć(x)={2xâ3â2x+2âifxâĽ2ifx<2â
For any x<2 consider the difference
f(x+Îx)âf(x)=â2(x+Îx)+2â(â2x+2)=â2Îxâ0
as Îxâ0. Therefore, this function is continuous for any x<2.
For any x>2 consider the difference
f(x+Îx)âf(x)=2(x+Îx)+2â(2x+2)=2Îxâ0
as Îxâ0. Therefore, this function is continuous for any x>2.
For x=2 consider one-sided limits:
Îâ+0limâf(2+Îx)=Îâ+0limâ(2(2+Îx)â3)=1
Îââ0limâf(2+Îx)=Îâ+0limâ(â2(2+Îx)+2)=â2
The one-sided limits are not equal, therefore, the function is not continuous at x=2.
5. Ć(x)={âŁx+2âŁ4âifxî =â2ifx=â2â
For any x>â2 consider the limit
Îâ0limâf(x+Îx)=Îâ0limââŁx+Îx+2âŁ
=Îâ0limâ(x+Îx+2)=x+2=f(x)
Therefore, the function is continuous for any x>â2.
For any x<â2 consider the limit
Îâ0limâf(x+Îx)=Îâ0limââŁx+Îx+2âŁ
=Îâ0limâ(âxâÎxâ2)=âxâ2=f(x)
Therefore, the function is continuous for any x<â2.
For x=â2 consider one-sided limits:
Îâ+0limâf(â2+Îx)=Îâ+0limââŁâ2+Îx+2âŁ=0
Îââ0limâf(â2+Îx)=Îââ0limââŁâ2+Îx+2âŁ=0
They are not equal to f(â2)=4. Therefore, the function is not continuous at x=â2.
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