1. Find the specific function values f(x, y) = x^2 + xy^3
(a) f(2, 3) (b) f(−3, −2)
f(2,3)=22+2⋅33=58f(−3,−2)=(−3)2+(−3)⋅(−2)3=33f\left( 2,3 \right) =2^2+2\cdot 3^3=58\\f\left( -3,-2 \right) =\left( -3 \right) ^2+\left( -3 \right) \cdot \left( -2 \right) ^3=33f(2,3)=22+2⋅33=58f(−3,−2)=(−3)2+(−3)⋅(−2)3=33
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