Graph the given curve and find the area of a bounded region.
x= 3y^2 - 9
"x=3y^2-9"
factoring;
"y=\\sqrt{\\frac{x+9}{3}}"
"y=(\\frac{x+9}{3})^{\\frac{1}{2}}"
to find the area we integrate the function with respect to x
"\\int_{-9}^{\\infin} (\\frac{x+9}{3})^{\\frac{1}{2}}dx"
the integral is divergent hence the area can not be found as it is unbounded.
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