What is the axis of symmetry for the graph of y=2x2-4x+2
Since
y=2x2−4x+2=2(x2−2x+1)=2(x−1)2,y=2x^2-4x+2 =2(x^2-2x+1) =2(x-1)^2,y=2x2−4x+2=2(x2−2x+1)=2(x−1)2,
we conclude that the axis of symmetry is x=1.x=1.x=1.
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