Question 2 [7]
Use sign table to determine the values of 𝑥 for which
x^2 + 9𝑥 + 20 ≤ 0.
x2+9x+20≤0 ⟹ (x+4)(x+5)≤0x^2+9x+20≤0\implies (x+4)(x+5)≤0x2+9x+20≤0⟹(x+4)(x+5)≤0
So, as we can see from the table, x∈[−5;−4]x\in[-5;-4]x∈[−5;−4]
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