F(x) = 5x2 -8x + 10
"D=b^2-4ac=64-4*50" <0
"\\forall x\\in\\R" F(x)>0
F'(x)=10x-8
F'(x)=0;x=0.8
min(F(x))=F(0.8)="\\frac{34}{5}"
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