Answer to Question #307860 in Calculus for justt

Question

Find the dy/dx of each of the following:

1.y=〖5x〗^3-〖4x〗^2+3x-6

2.y=∛x+4/x+√x

3.y=(3-x^2 )(x^3-x+1)

4.y=(x^2+1)(x+5+1/x)

5.y=(5x+1)/(2√x)

Answer 1

1.dy/dx=375x²-32x+3

2.$dy/dx=\frac{1}{3\sqrt[3]{x^2}}-\frac{4}{x^2}+\frac{1}{2\sqrt{x}}$

3.$y=3x^3-3x+3-x^5+x^4-x^2$

$dy/dx=9x^2-3-5x^4+4x^3-2x$

4.$y=x^3+5x^2+x+x+5+1/x$

$dy/dx=3x^2+10x+2-\frac{1}{x^2}$

5.$dy/dx=\frac{5}{4\sqrt{x}}-\frac{1}{4\sqrt[3]{x^2}}$