In January 2025
Answer to Question #304844 in Calculus for jin
Find the first derivative of y with respect to x. Use the given relation in its
implicit form.
a. x2 + y2 = a2
b. X2 + 4y2 = 4ay
"a. x^2 +y^2=a^2\\\\\n2x+2yy'=0\\\\\ny'=-\\frac{2x}{2y}\\\\\ny'=-\\frac{x}{y}\\\\\nb. x^2 +4y^2=4ay\\\\\n2x+8yy'=4ay'\\\\\n4ay'-8yy'=2x\\\\\ny'(4a-8y)=2x\\\\\ny'=\\frac{2x}{4a-8y}\\\\\ny'=\\frac{x}{2a-4y}\\\\"
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