Question #304840

Find the first derivative of y = (3x+4)2



Expert's answer

y′=((3x+4)2)′=2(3x+4)(3)y'=((3x+4)^2)'=2(3x+4)(3)

y′=6(3x+4)=18x+24y'=6(3x+4)=18x+24


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Canada #340153 on Dec 2023