Question #304618

the equation for a projectile height versus time is h(t)= -16^2+ Vot+ho

a tennis ball machine serves a ball vertically into the air from a height of two feet, with an initial speed of 120 feet per second . after how many seconds does the ball attain its maximum height


1
Expert's answer
2022-03-02T12:13:27-0500
h(t)=2+120t16t2,t0h(t)=2+120t-16t^2, t\ge0

Find the first derivative with respect to tt


h(t)=12032th'(t)=120-32t

Find the critical number(s)


h(t)=0=>12032t=0h'(t)=0=>120-32t=0

t=3.75 st=3.75\ s


Critical number: 3.75


If 0t<3.75,h(t)>0,h(t)0\le t<3.75, h'(t)>0, h(t) increases.

If t>3.75,h(t)<0,h(t)t>3.75, h'(t)<0, h(t) decreases.

The function h(t)h(t) has a local maximum at t=3.75.t=3.75. Since the function h(t)h(t) has the only extremum for t0,t\ge0, then the function h(t)h(t) has the absolute maximum at t=3.75.t=3.75.

The ball attains its maximum height after 3.753.75 seconds .



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