Six women and five men walk into an
appliance store at thesame time. There are five
salesperson available to help them.Find the
probability that a salesperson will first help at
least 2 women
we define the total number of men and women = (5+6) = 11
We define (11C5)=462
let X be the number of women to be helped first
P((x≥2) = 1-(P(X=0)+P(X=1)
We define p(x=0)=( (6C0)*(5C5) ) /(11C5)=1/462
We define P(x=1)=( (6C1)*(5C4) ) /(11C5)= 30/462
Thus p(x≥2) = 1 - ( (1/462) + 30/462) ) = (431/462)=0.932900432
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