Find the area bounded by the y-axis, the line y = 1, and the arc of y = sin x between x = 0 and x = 𝜋/2.
S=∫0π2(1−sinx)dx=(x+cosx))∣0π2==π2+cosπ2−cos0=π2−1S=\int_0^{\frac{\pi}{2}}(1-sinx)dx=(x+cosx))|_0^{\frac{\pi}{2}}=\\ =\frac{\pi}{2}+cos\frac{\pi}{2}-cos0=\frac{\pi}{2}-1S=∫02π(1−sinx)dx=(x+cosx))∣02π==2π+cos2π−cos0=2π−1
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