Answer to Question #301861 in Calculus for kazi

Question

Given: x = csct and y = cott. Find y’.

Answer 1

$y'=\frac{dy}{dx}=\frac{\frac{dy}{dt}}{\frac{dx}{dt}}=\frac{}{}=\frac{-\csc^2t}{-\cot t\csc t}=\sec t.$