Question #298083

a) Find the indefinite integral of the function

š‘¦ = 3š‘”2 + 2š‘’3š‘” + 2 + 2 cos 3š‘”


Expert's answer

∫ydt=∫(3t2+2e3t+2+2cos⁔3t)dt\int ydt=\int (3t^2+2e^{3t} +2+2\cos 3t)dt

=t3+23e3t+2t+23sin⁔3t+C=t^3+\dfrac{2}{3}e^{3t}+2t+\dfrac{2}{3}\sin 3t+C



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