Question #296745

f(x)=x²+x⁴+2ex


1
Expert's answer
2022-02-14T11:26:18-0500

Solution:

To find f'(x).

f(x)=x2+x4+2exf′(x)=2x+4x3+2exf(x)=x²+x⁴+2e^x \\ f'(x)=2x+4x^3+2e^x


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