Answer to Question #292340 in Calculus for Mistura

Question

Determine the zeros of the function y = k/2(sin(x)); 0 ≤ x ≤ π

Answer 1

Solution:

$y = \dfrac k2(\sin x); 0 ≤ x ≤ π$

Put y=0

$\Rightarrow \dfrac k2(\sin x)=0 \\\Rightarrow \sin x=0 \\\Rightarrow x=0,\,x=\pi$