Answer to Question #292334 in Calculus for Mistura

Question

Given the following three functions: l(X) = x+4; h(x) = 1/x and g(X) = 2 - 11x. Derive the composite function h(l(g(X))).

Answer 1

Solution:

$l(x) = x+4; h(x) = \dfrac 1x\ ;\ g(x) = 2 - 11x.$

Now, $h(l(g(x)))=h(l(2-11x))$

$=h(2-11x+4) \\=h(6-11x) \\=\dfrac 1{6-11x}$