Question

If A=2xz^2i-yzj+3xz^3k then what is the value of curlA?

Answer 1

$Curl~A=\begin{vmatrix} i & j & k \\ \frac{d}{dx} & \frac{d}{dy} & \frac{d}{dz}\\ 2xz^2 & -yz & 3xz^3 \end{vmatrix} \\ i(\frac{d}{dy}(3xz^3)-\frac{d}{dz}(-yz))-j(\frac{d}{dx}(3xz^3)-\frac{d}{dz}(2xz^2))+k(\frac{d}{dx}(-yz)-\frac{d}{dy}(2xz^2))\\ Curl~A=i(y)-j(3z^3-4xz)+0k\\ Curl~A=yi-(3z^3-4xz)j$