*SHOW SOLUTION*
1.
A metal washer is made from two concentric circles and its a ring shape.
Let "r_1=" the radius of inner circle
"r_2=" the radius of outer circle
Surface are
Given "2r_1=\\dfrac{1}{2}in, 2r_2=1 in."
Then
"A=\\pi(\\dfrac{1}{2}in)^2-\\pi(\\dfrac{1}{4}in)^2=\\dfrac{3\\pi}{16}in^2"
The area of one of the washer is "\\dfrac{3\\pi}{16}\\ in^2."
2. From the description of the given word problem, the vertical end of a trough is a trapezoid.
Given "a=4.4ft, b=3.2ft, h=3.5ft."
The area of a trapezoid is "A=\\dfrac{a+b}{2}h."
Substitute
The area of the end of the trough is "13.3ft^2."
3. The curved surface area of the dome is
Given "d=36ft=432in." Then
What must be paid for the golf leaf?
4. Volume of one billiard ball
Given "d=21in=1.75ft." Then the volume of 1000 ivory billiard balls is
The weight (mass) of 1000 ivory billiard balls is
"M=114lb\/ft^3 \\cdot(\\dfrac{5359.375\\pi}{6}\\ ft^3)"
"=319902.5\\ lb=145105.21\\ kg"
The weight (mass) of 1000 ivory billiard balls is "319902.5\\ lb" or "145105.21\\ kg."
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