Question

$\intop$ 1/x²-4x+3 dx=?

Answer 1

By the sum rule,

$\int(\frac{1}{x²}-4x+3)dx=$

$\int \frac{1}{x²}dx-\int4xdx+\int3dx$

Integrating each integral, we have

$=-\frac{1}{x}-2x²+3x+c$

( $c$ is added since it's an indefinite integral).