Question #280258

y=sin(2x)/x, x=Pi, dx=.25

find the differentiate


1
Expert's answer
2021-12-16T17:06:19-0500

dydx=2cos(2x)xsin(2x)x2.\frac{dy}{dx}=\frac{2cos(2x)}{x}-\frac{sin(2x)}{x^2}.

dy=[2cos(2x)xsin(2x)x2]dx.dy=[\frac{2cos(2x)}{x}-\frac{sin(2x)}{x^2}]dx.

When x=π,  dx=0.25:x=\pi, \;dx=0.25:

dy=[2cos(2π)πsin(2π)π2]0.25=0.5π0.1592.dy=[\frac{2cos(2\pi)}{\pi}-\frac{sin(2\pi)}{\pi^2}]*0.25=\frac{0.5}{\pi}\approx 0.1592.


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