Answer to Question #277184 in Calculus for nitish

Question

fine laplace transform : e^-2t u(t-3)

Answer 1

$\mathcal{L}_{t}\left[e^{-2 t} u(t-3)\right](s)\\ =e^{-3(s+2)}\left(\mathcal{L}_{t}[u(t)](s+2)+\int_{-3}^{0} e^{-(s+2) t} u(t) d t\right)$