1. Evaluate : (𝑥3 + 1
𝑥3
) dx.
∫(x3+1x3)dx=x44+x−2−2+C==x44−12x2+C\int(x^3+\frac{1}{x^3})dx=\frac{x^4}{4}+\frac{x^{-2}}{-2}+C=\\ =\frac{x^4}{4}-\frac{1}{2x^2}+C∫(x3+x31)dx=4x4+−2x−2+C==4x4−2x21+C
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