Solve the equation π = β«10π2t ππ‘ for T range 0 to T.
Solution;
"S=\\displaystyle \\int_0^T10e^{2t}dt"
"S=10\\displaystyle \\int_0^Te^{2t}dt"
"S=10[\\frac{e^{2t}}{2}]_0^T"
"S=5(e^{2T}-e^{0})"
"S=5(e^{2T}-1)"
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment