Solve the equation 𝑆 = ∫10𝑒2t 𝑑𝑡 for T range 0 to T.
Solution;
S=∫0T10e2tdtS=\displaystyle \int_0^T10e^{2t}dtS=∫0T10e2tdt
S=10∫0Te2tdtS=10\displaystyle \int_0^Te^{2t}dtS=10∫0Te2tdt
S=10[e2t2]0TS=10[\frac{e^{2t}}{2}]_0^TS=10[2e2t]0T
S=5(e2T−e0)S=5(e^{2T}-e^{0})S=5(e2T−e0)
S=5(e2T−1)S=5(e^{2T}-1)S=5(e2T−1)
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