Question #274274

Solve the equation 𝑆 = ∫10𝑒2t 𝑑𝑡 for T range 0 to T.




1
Expert's answer
2021-12-02T15:17:49-0500

Solution;

S=0T10e2tdtS=\displaystyle \int_0^T10e^{2t}dt


S=100Te2tdtS=10\displaystyle \int_0^Te^{2t}dt


S=10[e2t2]0TS=10[\frac{e^{2t}}{2}]_0^T

S=5(e2Te0)S=5(e^{2T}-e^{0})

S=5(e2T1)S=5(e^{2T}-1)



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