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Question #273216
The displacement,
y(m), of a body in damped oscillation is y=2e^-t sin sin 3t
.
The task is to:
Use the Product Rule to find an equation for the velocity of the object if v=dy/dt.
Expert's answer
1.
v
=
d
y
d
t
=
d
d
t
(
2
e
−
t
sin
(
3
t
)
)
v=\dfrac{dy}{dt}=\dfrac{d}{dt}(2e^{-t} \sin(3t))
v
=
d
t
d
y
=
d
t
d
(
2
e
−
t
sin
(
3
t
))
=
2
sin
(
3
t
)
d
d
t
(
e
−
t
)
+
2
e
−
t
d
d
t
(
sin
(
3
t
)
)
=2\sin(3t)\dfrac{d}{dt}(e^{-t})+2e^{-t}\dfrac{d}{dt}(\sin(3t))
=
2
sin
(
3
t
)
d
t
d
(
e
−
t
)
+
2
e
−
t
d
t
d
(
sin
(
3
t
))
=
2
sin
(
3
t
)
e
−
t
d
d
t
(
−
t
)
+
2
e
−
t
cos
(
3
t
)
d
d
t
(
3
t
)
=2\sin(3t)e^{-t}\dfrac{d}{dt}(-t)+2e^{-t}\cos(3t)\dfrac{d}{dt}(3t)
=
2
sin
(
3
t
)
e
−
t
d
t
d
(
−
t
)
+
2
e
−
t
cos
(
3
t
)
d
t
d
(
3
t
)
=
−
2
sin
(
3
t
)
e
−
t
+
6
e
−
t
cos
(
3
t
)
=-2\sin(3t)e^{-t}+6e^{-t}\cos(3t)
=
−
2
sin
(
3
t
)
e
−
t
+
6
e
−
t
cos
(
3
t
)
=
2
e
−
t
(
−
sin
(
3
t
)
+
3
cos
(
3
t
)
)
=2e^{-t}(-\sin(3t)+3\cos(3t))
=
2
e
−
t
(
−
sin
(
3
t
)
+
3
cos
(
3
t
))
v
=
d
y
d
t
=
2
e
−
t
(
−
sin
(
3
t
)
+
3
cos
(
3
t
)
)
v=\dfrac{dy}{dt}=2e^{-t}(-\sin(3t)+3\cos(3t))
v
=
d
t
d
y
=
2
e
−
t
(
−
sin
(
3
t
)
+
3
cos
(
3
t
))
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