Question #271937

Find the exact arc length of the curve


x = cos 3t, y = sin 3t ;(0 ≤ t ≤π)

1
Expert's answer
2021-12-05T17:45:59-0500

L=(x)2+(y)2dtL=\int \sqrt{(x')^2+(y')^2}dt


x=3sin3t,y=3cos3tx'=-3sin3t, y'=3cos3t


L=0π(3sin3t)2+(3cos3t)2dt=30πdt=3πL=\int^{\pi}_0 \sqrt{(-3sin3t)^2+(3cos3t)^2}dt=3\int^{\pi}_0 dt=3\pi


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